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CHemIStRY!!?

March 6th, 2010 | Author: admin

what mass of NaOH should be added to 300.0ml of water in order to prepare a solution with a pH=11.50?

Posted in Science Q&A

One Response to “CHemIStRY!!?”

  • mrfarabaugh:
    March 6, 2010 at 12:03 am

    If pH = 11.50 then pOH = 14-11.5 = 2.50

    [OH-] = 10 raised to the -2.5 power

    [OH-] = 0.00316 mol/L

    0.3 L x (0.00316 mol/L) x (40 g/mol) = 0.0379 g NaOH

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