what mass of NaOH should be added to 300.0ml of water in order to prepare a solution with a pH=11.50?
If pH = 11.50 then pOH = 14-11.5 = 2.50
[OH-] = 10 raised to the -2.5 power
[OH-] = 0.00316 mol/L
0.3 L x (0.00316 mol/L) x (40 g/mol) = 0.0379 g NaOH
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If pH = 11.50 then pOH = 14-11.5 = 2.50
[OH-] = 10 raised to the -2.5 power
[OH-] = 0.00316 mol/L
0.3 L x (0.00316 mol/L) x (40 g/mol) = 0.0379 g NaOH