CHemIStRY!!?

what mass of NaOH should be added to 300.0ml of water in order to prepare a solution with a pH=11.50?

One Response to “CHemIStRY!!?”

  • mrfarabaugh:

    If pH = 11.50 then pOH = 14-11.5 = 2.50

    [OH-] = 10 raised to the -2.5 power

    [OH-] = 0.00316 mol/L

    0.3 L x (0.00316 mol/L) x (40 g/mol) = 0.0379 g NaOH

Leave a Reply